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GetVidya Discussion Forum  |  Informals  |  Puzzlers Paradise (Moderators: vishal, abhishek)  |  Topic: find the digits ?? 0 Members and 1 Guest are viewing this topic. « previous next »
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Author Topic: find the digits ??  (Read 357 times)
gyan
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« on: February 03, 2008, 02:27:41 PM »

X Z Y+X Y Z = Y Z X
find the digits(X,Y,Z are all non zero digits )
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Mohd
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« Reply #1 on: February 03, 2008, 09:09:41 PM »

X=4,Y=9,Z=5
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nadeemoidu
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« Reply #2 on: February 03, 2008, 09:13:25 PM »

yes u r right.
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durgesh
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« Reply #3 on: January 15, 2009, 01:45:59 PM »

how to get this result ?

X Y Z + X Z Y = Y Z X

I proceeded like this,

(100x + 10y +z) + (100x + 10z + y) = (100y + 10z + x)

it gives, 199x - 89y + z =0

what's after that ? Huh
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abhishek
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« Reply #4 on: January 15, 2009, 02:43:05 PM »

After that Hit and Trial!!  Smiley
But with logic.
So lets solve it:
now you have an eq:
89y= 199x+z

you know each of the numbers are between 1 and 9 (You can guess why??).

so now lets look at the possible right hand term:
it can be ~200± 9 or ~400 ± 9 or ~ 600 ± 9 or ~ 800 ± 9.

it can not be more than that because max left hand side can be: 801 (89*9)

so look at ~200±9 so left hand side can be 89*2= 178 which is nearest but will not give any answer.
@ 400±9 89*4 (=356) is nearest, but answer can nt be find.
@600 ± 9; 89*7(=623) is nearest buut answer can nt be find.

@800±9 we have 89*9=801 whic lies in the region.

so from here you can calculate x=4; y=9 and z=5.
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durgesh
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« Reply #5 on: January 16, 2009, 01:07:41 PM »

cool... Smiley
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